(a) Draw the control flow graph for the printPrime() method.
(b) Consider test cases ti = (n = 3) and t2 = ( n = 5). Although these tour the same prime paths in printPrime(), they don't necessarily find the same faults. Design a simple fault that t2 would be more likely to discover than t1 would.the condition of while statement: numPrimes < n -> numPrimes <= n-1
the condition of the for statement in while: i <= numPrimes -> i < numPrimes
(c) For printPrime(), find a test case such that the corresponding test path visits the edge that connects the beginning of the while statementto the for statement without going through the body of the while loop.n = 1 or n = 0
(d) Enumerate the test requirements for node coverage, edge coverage,and prime path coverage for the path for printPrimes().node coverage:
nodes: [1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12]
test case: [1,2,3,4,5,6,7,8,2,9,10,11,10,12]
edge coverage:
edges: [1,2], [2,3], [2,9], [3,4], [4,5], [4,7], [5,6], [5,4], [6,7], [7,2], [7,8], [8,2], [9,10], [10,11], [10,12], [11,10]
test case: [1,2,3,4,5,4,5,6,7,8,2,9,10,11,10,12], [1,2,3,4,7,2,9,10,12]
prime path coverage:
prime path: [1,2,3,4,5,6,7,8], [1,2,3,4,7,8], [1,2,9,10,11], [1,2,9,10,12]
[2,3,4,5,6,7,8,2], [2,3,4,5,6,7,2], [2,3,4,7,8,2], [2,3,4,7,2]
[3,4,5,6,7,8,2,9,10,11], [3,4,5,6,7,2,9,10,11], [3,4,5,6,7,8,2,9,10,12], [3,4,5,6,7,2,9,10,12], [3,4,7,2,9,10,11], [3,4,7,2,9,10,12], [3,4,7,8,2,9,10,11], [3,4,7,8,2,9,10,12]
[4,5,4]
[5,4,5], [5,4,7,2,9,10,11], [5,4,7,2,9,10,12], [5,4,7,8,2,9,10,12], [5,4,7,8,2,9,10,11]
[7,2,3,4,5,6,7], [7,2,3,4,7]
[8,2,3,4,5,6,7,8], [8,2,3,4,7,8]
[10,11,10]
[11,10,11], [11,10,12]
test case: [1,2,9,10,12], [1,2,9,10,11,10,11,10,12]
[1,2,3,4,5,4,7,2,9,10,12], [1,2,3,4,5,4,7,2,9,10,11]
[1,2,3,4,5,4,7,8,2,9,10,12], [1,2,3,4,5,4,7,8,2,9,10,11]
[1,2,3,4,5,6,7,2,9,10,12], [1,2,3,4,5,6,7,2,9,10,11]
[1,2,3,4,5,6,7,8,2,9,10,12], [1,2,3,4,5,6,7,8,2,9,10,11]
[1,2,3,4,5,4,5,6,7,2,9,10,12], [1,2,3,4,5,4,5,6,7,2,9,10,11]
[1,2,3,4,7,2,9,10,12], [1,2,3,4,7,2,9,10,11]
[1,2,3,4,7,8,2,9,10,12], [1,2,3,4,7,8,2,9,10,11]